3x^2+x=1500

Solution for 3x^2+x=1500 equation:

3x^2+x=1500

We move all terms to the left:

3x^2+x-(1500)=0

a = 3; b = 1; c = -1500;
Δ = b2-4ac
Δ = 12-4·3·(-1500)
Δ = 18001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{18001}}{2*3}=\frac{-1-\sqrt{18001}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{18001}}{2*3}=\frac{-1+\sqrt{18001}}{6}
$